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0=5y^2-60
We move all terms to the left:
0-(5y^2-60)=0
We add all the numbers together, and all the variables
-(5y^2-60)=0
We get rid of parentheses
-5y^2+60=0
a = -5; b = 0; c = +60;
Δ = b2-4ac
Δ = 02-4·(-5)·60
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*-5}=\frac{0-20\sqrt{3}}{-10} =-\frac{20\sqrt{3}}{-10} =-\frac{2\sqrt{3}}{-1} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*-5}=\frac{0+20\sqrt{3}}{-10} =\frac{20\sqrt{3}}{-10} =\frac{2\sqrt{3}}{-1} $
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